A certain radioactive material can undergo th | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The rate of decay for each process is given by $\frac{dN_1}{dt} = -\lambda_1 N$,$\frac{dN_2}{dt} = -\lambda_2 N$,and $\frac{dN_3}{dt} = -\lambda_3

Vedclass · Accepted Answer

$\lambda_{eff} = \lambda_1 + \lambda_2 + \lambda_3$

Vedclass · Answer

(C) The rate of decay for each process is given by $\frac{dN_1}{dt} = -\lambda_1 N$,$\frac{dN_2}{dt} = -\lambda_2 N$,and $\frac{dN_3}{dt} = -\lambda_3 N$.The total rate of decay is the sum of the individual rates: $\frac{dN}{dt} = \frac{dN_1}{dt} + \frac{dN_2}{dt} + \frac{dN_3}{dt}$.Substituting the expressions,we get: $\frac{dN}{dt} = -\lambda_1 N - \lambda_2 N - \lambda_3 N = -(\lambda_1 + \lambda_2 + \lambda_3) N$.Comparing this with the general decay equation $\frac{dN}{dt} = -\lambda_{eff} N$,we find that the effective decay constant is $\lambda_{eff} = \lambda_1 + \lambda_2 + \lambda_3$.

$A$ certain radioactive material can undergo three different types of decay,each with a different decay constant $\lambda_1$,$\lambda_2$,and $\lambda_3$. Then the effective decay constant is:

Similar Questions

$37$ Rutherford equals

Explain the $\alpha$-decay process and give its appropriate example.

In the nuclear decay sequence given below:
$_Z{X^A} \to {}_{Z + 1}{Y^A} \to {}_{Z - 1}{K^{A - 4}} \to {}_{Z - 1}{K^{A - 4}}$
the particles emitted in the sequence are:

Curie is a unit of

Which spectrum is continuous?

Vedclass Test Series

Exam Paper Generator

Online Exam Module